35=-16t^2+60t+6

Solution for 35=-16t^2+60t+6 equation:

35=-16t^2+60t+6

We move all terms to the left:

35-(-16t^2+60t+6)=0

We get rid of parentheses

16t^2-60t-6+35=0

We add all the numbers together, and all the variables

16t^2-60t+29=0

a = 16; b = -60; c = +29;
Δ = b2-4ac
Δ = -602-4·16·29
Δ = 1744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1744}=\sqrt{16*109}=\sqrt{16}*\sqrt{109}=4\sqrt{109}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{109}}{2*16}=\frac{60-4\sqrt{109}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{109}}{2*16}=\frac{60+4\sqrt{109}}{32}
$